What is the d/(dt)(9sin(t)-sin(9t)) ?

The d/(dt)(9sin(t)-sin(9t)) is 9cos(t)-cos(9t)*9

What is the first d/(dt)(9sin(t)-sin(9t)) ?

The first d/(dt)(9sin(t)-sin(9t)) is 9cos(t)-cos(9t)*9

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\frac{d}{d t} (9 sin (t) - sin (9 t))

9 cos (t) - cos (9 t) \cdot 9

Solution steps

\frac{d}{d t} (9 sin (t) - sin (9 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (9 sin (t)) - \frac{d}{d t} (sin (9 t))

\frac{d}{d t} (9 sin (t)) = 9 cos (t)

\frac{d}{d t} (sin (9 t)) = cos (9 t) \cdot 9

= 9 cos (t) - cos (9 t) \cdot 9

\int sin (t) e^{- s t} d t

\frac{\partial}{\partial x} (e^{x y z^{9}})

d er i v a t i v e ln (9 - 7 x)

\int \frac{3 x ^{2} + 2 x + 1}{x} d x

\frac{d}{d x} (\frac{sin ( 2 x )}{x})

What is the d/(dt)(9sin(t)-sin(9t)) ?
The d/(dt)(9sin(t)-sin(9t)) is 9cos(t)-cos(9t)*9
What is the first d/(dt)(9sin(t)-sin(9t)) ?
The first d/(dt)(9sin(t)-sin(9t)) is 9cos(t)-cos(9t)*9