What is the derivative of f(x)=9-4/(x^2) ?

The derivative of f(x)=9-4/(x^2) is 8/(x^3)

What is the first derivative of f(x)=9-4/(x^2) ?

The first derivative of f(x)=9-4/(x^2) is 8/(x^3)

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derivative of

f (x) = 9 - \frac{4}{x ^{2}}

\frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (9 - \frac{4}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) - \frac{d}{d x} (\frac{4}{x ^{2}})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

= 0 - (- \frac{8}{x ^{3}})

Simplify

= \frac{8}{x ^{3}}

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What is the derivative of f(x)=9-4/(x^2) ?
The derivative of f(x)=9-4/(x^2) is 8/(x^3)
What is the first derivative of f(x)=9-4/(x^2) ?
The first derivative of f(x)=9-4/(x^2) is 8/(x^3)