What is the derivative of 1-e^{2t} ?

The derivative of 1-e^{2t} is -2e^{2t}

What is the first derivative of 1-e^{2t} ?

The first derivative of 1-e^{2t} is -2e^{2t}

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derivative of

1 - e^{2 t}

- 2 e^{2 t}

Solution steps

\frac{d}{d t} (1 - e^{2 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d}{d t} (e^{2 t})

\frac{d}{d t} (1) = 0

\frac{d}{d t} (e^{2 t}) = e^{2 t} \cdot 2

= 0 - e^{2 t} \cdot 2

Simplify

= - 2 e^{2 t}

\frac{1}{( s ^{2} + 6 s + 10 )}

\frac{d}{d t} (e^{2 t} sin (4 t))

2 x^{2} e^{x}

\frac{d}{d x} (x^{2} y^{2} z^{2})

(9.8) (5)

What is the derivative of 1-e^{2t} ?
The derivative of 1-e^{2t} is -2e^{2t}
What is the first derivative of 1-e^{2t} ?
The first derivative of 1-e^{2t} is -2e^{2t}