What is the limit as x approaches 0+of x/(sqrt(x)-1) ?

The limit as x approaches 0+of x/(sqrt(x)-1) is 0

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limit as x approaches 0+of x/(sqrt(x)-1)

x \to 0 + lim (\frac{x}{x - 1})

0

Solution steps

x \to 0 + lim (\frac{x}{x - 1})

Plug in the value

x = 0

= \frac{0}{0 - 1}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

f (x) = (x - 7) (5 x + 1)

e^{\frac{1}{t}}

\int \frac{x}{x + 6} d x

\frac{d}{d x} (e^{x} + 2^{(- x)} + 2 cos (x) - 6)

\frac{d y}{d x} + 8 y = e^{x} y^{- 6}

What is the limit as x approaches 0+of x/(sqrt(x)-1) ?
The limit as x approaches 0+of x/(sqrt(x)-1) is 0