integral from 0 to 4 of sqrt(1+x)

Lösung

\int_{0}^{4} 1 + x d x

\frac{10 5 - 2}{3}

Dezimale

6.78689 \dots

Schritte zur Lösung

\int_{0}^{4} 1 + x d x

Wende U-Substitution an

= \int_{1}^{5} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{5}

Berechne die Grenzen:

\frac{10 5}{3} - \frac{2}{3}

= \frac{10 5}{3} - \frac{2}{3}

Vereinfache

= \frac{10 5 - 2}{3}

\int \frac{- 1}{1 - x} d x

\int_{1}^{3} (- x^{2} + 4 x - 3) d x

x \to (0) lim (\frac{ln ( x )}{x})

x \to 1 + lim (\frac{∣ x - 1 ∣}{x - 1})

\frac{\partial}{\partial x} (\frac{- x}{y ^{2} + x ^{2}})