What is the tangent of f(x)=(18)/((2x+4)^2),\at x=9 ?

The tangent of f(x)=(18)/((2x+4)^2),\at x=9 is y=-9/1331 x+261/2662

tangent of f(x)=(18)/((2x+4)^2),\at x=9

tangent of

f (x) = \frac{18}{( 2 x + 4 ) ^{2}}, at x = 9

y = - \frac{9}{1331} x + \frac{261}{2662}

Solution steps

Find the tangent point:

(9, \frac{9}{242})

Find the slope of

f (x) = \frac{18}{( 2 x + 4 ) ^{2}} : \frac{df ( x )}{d x} = - \frac{9}{( x + 2 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{1331}

Find the line with slope m=

- \frac{9}{1331}

and passing through

(9, \frac{9}{242}) : y = - \frac{9}{1331} x + \frac{261}{2662}

y = - \frac{9}{1331} x + \frac{261}{2662}

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What is the tangent of f(x)=(18)/((2x+4)^2),\at x=9 ?
The tangent of f(x)=(18)/((2x+4)^2),\at x=9 is y=-9/1331 x+261/2662