What is the derivative of e^{2x}+e^{3x} ?

The derivative of e^{2x}+e^{3x} is e^{2x}*2+e^{3x}*3

What is the first derivative of e^{2x}+e^{3x} ?

The first derivative of e^{2x}+e^{3x} is e^{2x}*2+e^{3x}*3

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\frac{d}{d x} (e^{2 x} + e^{3 x})

e^{2 x} \cdot 2 + e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (e^{2 x} + e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= e^{2 x} \cdot 2 + e^{3 x} \cdot 3

y^{^{'}} - 5 y = 10

\frac{d}{d x} (x^{9} ln (x))

\frac{d y}{d x} = - \frac{3 x}{y}

\frac{d}{d x} (e^{a t} sin (b t))

\int cos (4 θ) d θ

What is the derivative of e^{2x}+e^{3x} ?
The derivative of e^{2x}+e^{3x} is e^{2x}*2+e^{3x}*3
What is the first derivative of e^{2x}+e^{3x} ?
The first derivative of e^{2x}+e^{3x} is e^{2x}*2+e^{3x}*3