sin(2x)dx+cos(7y)dy=0

Lösung

sin (2 x) d x + cos (7 y) d y = 0

y = \frac{arcsin ( \frac{7}{2} cos ( 2 x ) + c _{1} )}{7} + \frac{2 πn}{7}, y = \frac{π}{7} + \frac{arcsin ( - \frac{7}{2} cos ( 2 x ) - c _{1} )}{7} + \frac{2 πn}{7}

Schritte zur Lösung

sin (2 x) d x + cos (7 y) d y = 0

Solve separable ODE:

y = \frac{arcsin ( \frac{7}{2} cos ( 2 x ) + c _{1} )}{7} + \frac{2 πn}{7}, y = \frac{π}{7} + \frac{arcsin ( - \frac{7}{2} cos ( 2 x ) - c _{1} )}{7} + \frac{2 πn}{7}

y = \frac{arcsin ( \frac{7}{2} cos ( 2 x ) + c _{1} )}{7} + \frac{2 πn}{7}, y = \frac{π}{7} + \frac{arcsin ( - \frac{7}{2} cos ( 2 x ) - c _{1} )}{7} + \frac{2 πn}{7}

e x p an d (x^{2} - 3 x + 2) (2 x^{3} + 1)

\int_{1}^{2} \frac{3}{x} + \frac{5}{x ^{2}} d x

x \to \infty lim ((lo g_{2} (x))^{2})

im pl i c i t \frac{d y}{d x}, 5 + 4 x = sin (x y^{3})

\frac{d}{d x} ((4 x^{3} + 5 x)^{4})