derivative of ax^3+bx^2+c

解答

\frac{d}{d x} (a x^{3} + b x^{2} + c)

3 a x^{2} + 2 b x

求解步骤

\frac{d}{d x} (a x^{3} + b x^{2} + c)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{3}) + \frac{d}{d x} (b x^{2}) + \frac{d c}{d x}

\frac{d}{d x} (a x^{3}) = 3 a x^{2}

\frac{d}{d x} (b x^{2}) = 2 b x

\frac{d c}{d x} = 0

= 3 a x^{2} + 2 b x + 0

化简

= 3 a x^{2} + 2 b x

\frac{d y}{d x} = e^{2 x} - 3 y, y (0) = 1

d er i v a t i v e 4 sec (x) - 8 cos (x)

\int_{0}^{1} x e^{- 7 x^{2}} d x

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