derivative of arcsin(4-3x)

Lösung

\frac{d}{d x} (arcsin (4 - 3 x))

- \frac{3}{- 9 x ^{2} + 24 x - 15}

Schritte zur Lösung

\frac{d}{d x} (arcsin (4 - 3 x))

Wende die Kettenregel an:

\frac{1}{1 - ( 4 - 3 x ) ^{2}} \frac{d}{d x} (4 - 3 x)

= \frac{1}{1 - ( 4 - 3 x ) ^{2}} \frac{d}{d x} (4 - 3 x)

\frac{d}{d x} (4 - 3 x) = - 3

= \frac{1}{1 - ( 4 - 3 x ) ^{2}} (- 3)

Vereinfache

\frac{1}{1 - ( 4 - 3 x ) ^{2}} (- 3) : - \frac{3}{- 9 x ^{2} + 24 x - 15}

= - \frac{3}{- 9 x ^{2} + 24 x - 15}

t^{2} \frac{d y}{d t} + t y = 6

n = 0 \sum \infty \frac{n}{3} (\frac{2}{3})^{n}

\int_{1}^{5} \frac{x ^{2} - 1}{x} d x

\frac{d}{d x} (4 x^{3} ln (x))

x \to - \infty lim (\frac{2 x ^{2} + 3}{2 x + 3})