What is the solution for y^'= x/(10y) ?

The solution for y^'= x/(10y) is y=sqrt((x^2)/(10)+c_{1)},y=-sqrt((x^2)/(10)+c_{1)}

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y^'= x/(10y)

y^{^{'}} = \frac{x}{10 y}

y = \frac{x ^{2}}{10} + c_{1}, y = - \frac{x ^{2}}{10} + c_{1}

Solution steps

y^{'} (x) = \frac{x}{10 y}

Solve separable ODE:

y = \frac{x ^{2}}{10} + c_{1}, y = - \frac{x ^{2}}{10} + c_{1}

y = \frac{x ^{2}}{10} + c_{1}, y = - \frac{x ^{2}}{10} + c_{1}

\int sec (x) tan^{5} (x) d x

\frac{\partial}{\partial x} (x + x y + y)

y^{^{'}} = (1 - 2 x) y^{2}

\frac{d}{d x} (4 x e^{2 x})

\frac{d}{d x} (\frac{x - 1}{x + 4})

What is the solution for y^'= x/(10y) ?
The solution for y^'= x/(10y) is y=sqrt((x^2)/(10)+c_{1)},y=-sqrt((x^2)/(10)+c_{1)}