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Popular Calculus >

y^'=(1-2x)y^2

Solution

y^{^{'}} = (1 - 2 x) y^{2}

Solution

y = - \frac{1}{x - x ^{2} + c _{1}}

Solution steps

y^{'} (x) = (1 - 2 x) y^{2}

Solve separable ODE:

y = - \frac{1}{x - x ^{2} + c _{1}}

y = - \frac{1}{x - x ^{2} + c _{1}}

Graph

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e x p an d \frac{( x ^{(3)} - 1 ) ( x + 1 ) ^{(3)}}{x + 2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(1-2x)y^2 ?
The solution for y^'=(1-2x)y^2 is y=-1/(x-x^2+c_{1)}