integral from 1 to 3 of (x^2-1/(4x^2))

Lösung

\int_{1}^{3} (x^{2} - \frac{1}{4 x ^{2}}) d x

\frac{17}{2}

Dezimale

8.5

Schritte zur Lösung

\int_{1}^{3} x^{2} - \frac{1}{4 x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} \frac{1}{4 x ^{2}} d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} \frac{1}{4 x ^{2}} d x = \frac{1}{6}

= \frac{26}{3} - \frac{1}{6}

Vereinfache

\frac{26}{3} - \frac{1}{6} : \frac{17}{2}

= \frac{17}{2}

e x p an d \frac{( x ^{(3)} - 1 ) ( x + 1 ) ^{(3)}}{x + 2}

\frac{d}{d x} ((3 cos (x)) (ln (1 + x)))

\int \frac{7 sec ^{2} ( 2 x )}{3 - 5 tan ( 2 x )} d x

\int arcsinh (x) d x

x \to + 0 + lim (x^{12} ln (x))