y+2y^7=(y^3+6x)y^'

Lösung

y + 2 y^{7} = (y^{3} + 6 x) y^{^{'}}

y = 3 \frac{1 + 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}, y = 3 \frac{1 - 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}

Schritte zur Lösung

y + 2 y^{7} = (y^{3} + 6 x) y^{'} (x)

Solve exact ODE:

y = 3 \frac{1 + 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}, y = 3 \frac{1 - 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}

y = 3 \frac{1 + 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}, y = 3 \frac{1 - 1 + 12 x ( 3 c _{1} - 6 x )}{2 ( 3 c _{1} - 6 x )}

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in v erse l a pl a ce \frac{( s + 5 )}{s ^{2} + 5 s + 4}