derivative-0.05(t+1.1)^{2.2}+0.7t+0.9

解

導関数

- 0.05 (t + 1.1)^{2.2} + 0.7 t + 0.9

- 0.11 (t + 1.1)^{1.2} + 0.7

解答ステップ

\frac{d}{d t} (- 0.05 (t + 1.1)^{2.2} + 0.7 t + 0.9)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (0.05 (t + 1.1)^{2.2}) + \frac{d}{d t} (0.7 t) + \frac{d}{d t} (0.9)

\frac{d}{d t} (0.05 (t + 1.1)^{2.2}) = 0.11 (t + 1.1)^{1.2}

\frac{d}{d t} (0.7 t) = 0.7

\frac{d}{d t} (0.9) = 0

= - 0.11 (t + 1.1)^{1.2} + 0.7 + 0

簡素化

= - 0.11 (t + 1.1)^{1.2} + 0.7