What is the tangent of sqrt(x)(4.2) ?

The tangent of sqrt(x)(4.2) is y=(2.1)/(sqrt(a_{0))}x+(21sqrt(a_{0)})/(10)

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tangent of sqrt(x)(4.2)

tangent of

x (4.2)

y = \frac{2.1}{a _{0}} x + \frac{21 a _{0}}{10}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} \cdot 4.2)

Find the slope of

y = x 4.2 : \frac{d y}{d x} = \frac{2.1}{x}

Compute the slope of

y = x 4.2

x = a_{0} : m = \frac{2.1}{a _{0}}

Find the line with slope m=

\frac{2.1}{a _{0}}

and passing through

(a_{0}, a_{0} 4.2) : y = \frac{2.1}{a _{0}} x + \frac{21 a _{0}}{10}

y = \frac{2.1}{a _{0}} x + \frac{21 a _{0}}{10}

\frac{d}{d x} (tan (x + c))

\int \frac{( x ^{3} + 20 x ^{2} + 8 )}{x + 20} d x

\int 7 e^{x^{2}} d x

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\int (6 x + 4) d x

What is the tangent of sqrt(x)(4.2) ?
The tangent of sqrt(x)(4.2) is y=(2.1)/(sqrt(a_{0))}x+(21sqrt(a_{0)})/(10)