What is the integral of (ln(y))/(ln(y)) ?

The integral of (ln(y))/(ln(y)) is y+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ln(y))/(ln(y))

\int \frac{ln ( y )}{ln ( y )} d y

y + C

Solution steps

\int \frac{ln ( y )}{ln ( y )} d y

Simplify

= \int 1 d y

Integral of a constant:

\int a d x = a x

= 1 \cdot y

Simplify

= y

Add a constant to the solution

= y + C

e^{t^{2}} y^{^{'}} + (t + t y^{2}) = 0, y (0) = 1

\frac{64 x}{x ^{2} + 64}

\frac{\partial}{\partial y} (2 x^{3} - x^{2} y)

\int (t^{2} - 1) (4 + 3 t) d t

f (x) = x^{4}, at x = 1

What is the integral of (ln(y))/(ln(y)) ?
The integral of (ln(y))/(ln(y)) is y+C