derivative of-3/(x^2+4e^{2x})

Lösung

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

\frac{6}{x ^{3}} + 8 e^{2 x}

Schritte zur Lösung

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{3}{x ^{2}}) + \frac{d}{d x} (4 e^{2 x})

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{d}{d x} (4 e^{2 x}) = 8 e^{2 x}

= - (- \frac{6}{x ^{3}}) + 8 e^{2 x}

Vereinfache

= \frac{6}{x ^{3}} + 8 e^{2 x}

f (x) = \frac{x ^{2}}{3}

\frac{\partial}{\partial y} (2 x + 3 y - 7)

\int \frac{d}{1} (cos (2 x)) d x

n = 1 \sum \infty (1 - p)^{3 n}

x \to 1 lim (3 x^{2} - 1)