What is the derivative of (5x+8^2) ?

The derivative of (5x+8^2) is 10(5x+8)

What is the first derivative of (5x+8^2) ?

The first derivative of (5x+8^2) is 10(5x+8)

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\frac{d}{d x} ((5 x + 8)^{2})

10 (5 x + 8)

Solution steps

\frac{d}{d x} ((5 x + 8)^{2})

Apply the chain rule:

2 (5 x + 8) \frac{d}{d x} (5 x + 8)

= 2 (5 x + 8) \frac{d}{d x} (5 x + 8)

\frac{d}{d x} (5 x + 8) = 5

= 2 (5 x + 8) \cdot 5

Simplify

= 10 (5 x + 8)

y^{^{''}} + 25 y = 5 csc^{2} (5 t)

\frac{d}{d x} (x^{3 s i n (x)})

\int e^{y t} \cdot sin (k t) d t

(2 t)^{^{'}}

\int \frac{1}{x ^{2} - 4 x + 13} d x

What is the derivative of (5x+8^2) ?
The derivative of (5x+8^2) is 10(5x+8)
What is the first derivative of (5x+8^2) ?
The first derivative of (5x+8^2) is 10(5x+8)