derivative f(x)=(x^2-1)/(x+1)

Lösung

ableitung von

f (x) = \frac{x ^{2} - 1}{x + 1}

1

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 1}{x + 1})

Vereinfache

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{d}{d x} (x - 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Vereinfache

= 1

x \to 1 + lim (ln (x^{5} - 1))

y^{^{'}} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 3

d er i v a t i v e y = e^{7}

y^{^{''}} - 6 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 7

e^{y} (1 + x^{2}) d y - 2 x (1 + e^{y}) d x = 0