What is the tangent of f(x)=x^2-3,(3,6) ?

The tangent of f(x)=x^2-3,(3,6) is y=6x-12

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tangent of f(x)=x^2-3,(3,6)

tangent of

f (x) = x^{2} - 3, (3, 6)

y = 6 x - 12

Solution steps

Find the slope of

f (x) = x^{2} - 3 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(3, 6) : y = 6 x - 12

y = 6 x - 12

ma c l a u r in \frac{4 x}{x ^{2} + 2 x - 3}

\frac{d}{d x} (\frac{1}{5 - 11 e ^{x}})

\int \frac{2}{3} x^{\frac{1}{2}} d x

\int \frac{x ^{3}}{e ^{x^{2}}} d x

x \to 0 lim (\frac{1}{3 + 2 ^{\frac{1}{x}}})

What is the tangent of f(x)=x^2-3,(3,6) ?
The tangent of f(x)=x^2-3,(3,6) is y=6x-12