What is the integral of sin(20x) ?

The integral of sin(20x) is -1/20 cos(20x)+C

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integral of sin(20x)

\int sin (20 x) d x

- \frac{1}{20} cos (20 x) + C

Solution steps

\int sin (20 x) d x

Apply u-substitution

= \int sin (u) \frac{1}{20} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{20} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{20} (- cos (u))

Substitute back

u = 20 x

= \frac{1}{20} (- cos (20 x))

Simplify

= - \frac{1}{20} cos (20 x)

Add a constant to the solution

= - \frac{1}{20} cos (20 x) + C

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