integral of 1/2 x+2

Lösung

\int \frac{1}{2} x + 2 d x

\frac{x ^{2}}{4} + 2 x + C

Schritte zur Lösung

\int \frac{1}{2} x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{2} x d x + \int 2 d x

\int \frac{1}{2} x d x = \frac{x ^{2}}{4}

\int 2 d x = 2 x

= \frac{x ^{2}}{4} + 2 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{2}}{4} + 2 x + C

\int \frac{6}{( x - 9 ) ( x - 3 )} d x

\int (x + 1)^{- \frac{1}{2}} - π \cdot cos (π x) d x

\int \frac{2 x + 1}{2 x ^{2} + 3 x - 2} d x

\int \frac{2 x ^{2} - 12 x + 4}{x ^{3} - 4 x ^{2}} d x

\int \frac{1}{t ^{\frac{1}{2}} - t ^{\frac{1}{4}}} d t