integral from-infinity to 8 of xe^{x/4}

解答

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x

16 e^{2}

十进制

118.22489 \dots

求解步骤

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x

计算不定积分:

\int x e^{\frac{x}{4}} d x = 4 e^{\frac{x}{4}} x - 16 e^{\frac{x}{4}} + C

带入上下限计算后得:

\int_{- \infty}^{8} x e^{\frac{x}{4}} d x = 16 e^{2} - 0

= 16 e^{2} - 0

化简

= 16 e^{2}

t an g e n t f (x) = 2 x^{4} - 11 x^{2}, at x = 1

\int \frac{x}{2 x ^{2} + 3} d x

7 + e^{- 5 x} y^{^{'}} = 0

\int \frac{2 x - 1}{( x - 1 ) ( x - 2 )} d x

l a pl a ce t r an s f or m sin (w)