What is the integral of x^2-8x+15 ?

The integral of x^2-8x+15 is (x^3)/3-4x^2+15x+C

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integral of x^2-8x+15

\int x^{2} - 8 x + 15 d x

\frac{x ^{3}}{3} - 4 x^{2} + 15 x + C

Solution steps

\int x^{2} - 8 x + 15 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 8 x d x + \int 15 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 8 x d x = 4 x^{2}

\int 15 d x = 15 x

= \frac{x ^{3}}{3} - 4 x^{2} + 15 x

Add a constant to the solution

= \frac{x ^{3}}{3} - 4 x^{2} + 15 x + C

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What is the integral of x^2-8x+15 ?
The integral of x^2-8x+15 is (x^3)/3-4x^2+15x+C