integral of 9x-3

解答

\int 9 x - 3 d x

\frac{9 x ^{2}}{2} - 3 x + C

求解步骤

\int 9 x - 3 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x d x - \int 3 d x

\int 9 x d x = \frac{9 x ^{2}}{2}

\int 3 d x = 3 x

= \frac{9 x ^{2}}{2} - 3 x

解答补常数

= \frac{9 x ^{2}}{2} - 3 x + C

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