y^{''}-y^'+4y=2sin(2x)

Lösung

y^{^{''}} - y^{^{'}} + 4 y = 2 sin (2 x)

y = e^{\frac{x}{2}} (c_{1} cos (\frac{15 x}{2}) + c_{2} sin (\frac{15 x}{2})) + cos (2 x)

Schritte zur Lösung

y^{''} (x) - y^{'} (x) + 4 y = 2 sin (2 x)

Solve linear ODE:

y = e^{\frac{x}{2}} (c_{1} cos (\frac{15 x}{2}) + c_{2} sin (\frac{15 x}{2})) + cos (2 x)

y = e^{\frac{x}{2}} (c_{1} cos (\frac{15 x}{2}) + c_{2} sin (\frac{15 x}{2})) + cos (2 x)

\int_{0}^{7} 49 + x^{2} d x

\frac{d}{d x} ((x - 2) (3 x + 8))

\int \frac{x + 2}{5 x + 6} d x

\frac{d}{d x} (e^{x} cos (x) - sin (x) e^{x})

y^{^{''}} + 36 y^{^{'}} = 0