integral from 0 to 1 of 36pi(x^2-x^{10})

解

\int_{0}^{1} 36 π (x^{2} - x^{10}) d x

\frac{96 π}{11}

十進法表記

27.41753 \dots

解答ステップ

\int_{0}^{1} 36 π (x^{2} - x^{10}) d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 36 π \cdot \int_{0}^{1} x^{2} - x^{10} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 36 π (\int_{0}^{1} x^{2} d x - \int_{0}^{1} x^{10} d x)

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} x^{10} d x = \frac{1}{11}

= 36 π (\frac{1}{3} - \frac{1}{11})

簡素化

36 π (\frac{1}{3} - \frac{1}{11}) : \frac{96 π}{11}

= \frac{96 π}{11}