integral from 0 to pi of (2sin(x))

Lösung

\int_{0}^{π} (2 sin (x)) d x

4

Schritte zur Lösung

\int_{0}^{π} 2 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{0}^{π}

Berechne die Grenzen:

2

= 2 \cdot 2

Vereinfache

= 4

\int_{0}^{3} x e^{x^{2}} d x

\int_{0}^{1} \frac{1}{x ^{4} - 1} d x

\int_{0}^{2} \frac{x}{x ^{2} - 1} d x

\int_{0}^{π} 1 + sin (2 x) d x

\int_{0}^{\frac{π}{2}} \frac{1}{1 - sin ( x )} d x