integral from-1 to 2 of x/(x^2+1)

Lösung

\int_{- 1}^{2} \frac{x}{x ^{2} + 1} d x

\frac{1}{2} (ln (5) - ln (2))

Dezimale

0.45814 \dots

Schritte zur Lösung

\int_{- 1}^{2} \frac{x}{x ^{2} + 1} d x

Wende U-Substitution an

= \int_{2}^{5} \frac{1}{2 u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{2}^{5} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} [ln ∣ u ∣]_{2}^{5}

Berechne die Grenzen:

ln (5) - ln (2)

= \frac{1}{2} (ln (5) - ln (2))

\int_{0}^{\frac{1}{2}} \frac{1}{x ln ^{2} ( x )} d x

\int_{0}^{\infty} \frac{1}{2 + x ^{2}} d x

\int_{1}^{6} 2^{x} d x

\int_{2}^{3} x e^{2 x} d x

\int_{0}^{5} \frac{10}{x} d x