integral from 0 to 2 of |2-x|

Lösung

\int_{0}^{2} ∣ 2 - x ∣ d x

2

Schritte zur Lösung

\int_{0}^{2} ∣ 2 - x ∣ d x

Entferne die Extremwerte

= \int_{0}^{2} 2 - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 d x - \int_{0}^{2} x d x

\int_{0}^{2} 2 d x = 4

\int_{0}^{2} x d x = 2

= 4 - 2

Vereinfache

= 2

\int_{0}^{π} \frac{1}{1 + sin ( x )} d x

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