integral from 0 to 2 of x^2+x+1

解

\int_{0}^{2} x^{2} + x + 1 d x

\frac{20}{3}

十進法表記

6.66666 \dots

解答ステップ

\int_{0}^{2} x^{2} + x + 1 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x + \int_{0}^{2} x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= \frac{8}{3} + 2 + 2

簡素化

\frac{8}{3} + 2 + 2 : \frac{20}{3}

= \frac{20}{3}