integral from 1 to 2 of 4/(x^5)

Lösung

\int_{1}^{2} \frac{4}{x ^{5}} d x

\frac{15}{16}

Dezimale

0.9375

Schritte zur Lösung

\int_{1}^{2} \frac{4}{x ^{5}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{2} \frac{1}{x ^{5}} d x

Wende die Potenzregel an

= 4 [- \frac{1}{4 x ^{4}}]_{1}^{2}

Berechne die Grenzen:

\frac{15}{64}

= 4 \cdot \frac{15}{64}

Vereinfache

= \frac{15}{16}

\int_{0}^{5} x^{2} + 2 x - 15 d x

\int_{0}^{3} (3 t - 1)^{52} d t

\int_{1}^{5} 9 d x

\int_{0}^{1} (4 x - 1)^{2} d x

\int_{0}^{3} 1 + \frac{81}{64} x d x