integral from 1 to x^2 of ln(t)

Lösung

\int_{1}^{x^{2}} ln (t) d t

2 x^{2} ln (x) - x^{2} + 1

Schritte zur Lösung

\int_{1}^{x^{2}} ln (t) d t

Wende die partielle Integration an

= [t ln (t) - \int 1 d t]_{1}^{x^{2}}

\int 1 d t = t

= [t ln (t) - t]_{1}^{x^{2}}

Berechne die Grenzen:

2 x^{2} ln (x) - x^{2} + 1

= 2 x^{2} ln (x) - x^{2} + 1

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