What is the integral from 0 to 4 of (3x^2+4x+7) ?

The integral from 0 to 4 of (3x^2+4x+7) is 124

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integral from 0 to 4 of (3x^2+4x+7)

\int_{0}^{4} (3 x^{2} + 4 x + 7) d x

124

Solution steps

\int_{0}^{4} 3 x^{2} + 4 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 x^{2} d x + \int_{0}^{4} 4 x d x + \int_{0}^{4} 7 d x

\int_{0}^{4} 3 x^{2} d x = 64

\int_{0}^{4} 4 x d x = 32

\int_{0}^{4} 7 d x = 28

= 64 + 32 + 28

Simplify

= 124

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What is the integral from 0 to 4 of (3x^2+4x+7) ?
The integral from 0 to 4 of (3x^2+4x+7) is 124