integral from 1 to 6 of |t^2-2t-15|

Lösung

\int_{1}^{6} t^{2} - 2 t - 15 d t

47

Schritte zur Lösung

\int_{1}^{6} t^{2} - 2 t - 15 d t

Entferne die Extremwerte

= \int_{1}^{5} - t^{2} + 2 t + 15 d t + \int_{5}^{6} t^{2} - 2 t - 15 d t

\int_{1}^{5} - t^{2} + 2 t + 15 d t = \frac{128}{3}

\int_{5}^{6} t^{2} - 2 t - 15 d t = \frac{13}{3}

= \frac{128}{3} + \frac{13}{3}

Vereinfache

\frac{128}{3} + \frac{13}{3} : 47

= 47

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