integral from 0 to 1 of \sqrt[4]{x}+1

Lösung

\int_{0}^{1} 4 x + 1 d x

\frac{9}{5}

Dezimale

1.8

Schritte zur Lösung

\int_{0}^{1} 4 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 4 x d x = \frac{4}{5}

\int_{0}^{1} 1 d x = 1

= \frac{4}{5} + 1

Vereinfache

\frac{4}{5} + 1 : \frac{9}{5}

= \frac{9}{5}

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