What is the integral from 1 to 3 of 2sqrt(x) ?

The integral from 1 to 3 of 2sqrt(x) is 2(2sqrt(3)-2/3)

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integral from 1 to 3 of 2sqrt(x)

\int_{1}^{3} 2 x d x

2 (23 - \frac{2}{3})

Decimal

5.59486 \dots

Solution steps

\int_{1}^{3} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{3} x d x

Apply the Power Rule

= 2 [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{3}

Compute the boundaries:

23 - \frac{2}{3}

= 2 (23 - \frac{2}{3})

\int_{1}^{e} (x + \frac{1}{x}) d x

\int_{- 5}^{- 2} \frac{1}{( x + 3 ) ^{2}} d x

\int_{0}^{5} (- 2 x^{2} + 10 x) d x

\int_{4}^{16} (x - 1) x d x

\int_{0}^{3} (x - 3)^{3} d x

What is the integral from 1 to 3 of 2sqrt(x) ?
The integral from 1 to 3 of 2sqrt(x) is 2(2sqrt(3)-2/3)