integral from 2 to 5 of (x^3+2)

Lösung

\int_{2}^{5} (x^{3} + 2) d x

\frac{633}{4}

Dezimale

158.25

Schritte zur Lösung

\int_{2}^{5} x^{3} + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} x^{3} d x + \int_{2}^{5} 2 d x

\int_{2}^{5} x^{3} d x = \frac{609}{4}

\int_{2}^{5} 2 d x = 6

= \frac{609}{4} + 6

Vereinfache

\frac{609}{4} + 6 : \frac{633}{4}

= \frac{633}{4}

\int_{0}^{0.5} \frac{1}{1 + x ^{4}} d x

\int_{0}^{3} e^{- y^{2}} d y

\int_{0}^{3} x (x - 3) (x - 1) d x

\int_{0}^{2} \frac{x ^{2}}{x ^{2} + 1} d x

\int_{1}^{2} 1 + \frac{9 x}{4} d x