integral from 1 to 2 of (x-1)^3

Lösung

\int_{1}^{2} (x - 1)^{3} d x

\frac{1}{4}

Dezimale

0.25

Schritte zur Lösung

\int_{1}^{2} (x - 1)^{3} d x

Wende U-Substitution an

= \int_{0}^{1} u^{3} d u

Wende die Potenzregel an

= [\frac{u ^{4}}{4}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{4}

= \frac{1}{4}

\int_{2}^{4} 25 - x^{2} d x

\int_{0}^{π} t \cdot cos (n t) d t

\int_{0}^{4} x e^{3 x} d x

\int_{0}^{\frac{1}{2}} x - 2 x^{2} d x

\int_{- 2}^{2} x^{3} (2 + x^{4})^{3} d x