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人気のある微分積分 >

integral from-1 to 0 of 1/(1+cos(t))

解

\int_{- 1}^{0} \frac{1}{1 + cos ( t )} d t

解

tan (\frac{1}{2})

+1

十進法表記

0.54630 \dots

解答ステップ

\int_{- 1}^{0} \frac{1}{1 + cos ( t )} d t

u置換積分法を適用する

= \int_{- t a n (\frac{1}{2})}^{0} 1 d u

定数の積分:

\int a d x = a x

= [1 \cdot u]_{- t a n (\frac{1}{2})}^{0}

簡素化

= [u]_{- t a n (\frac{1}{2})}^{0}

限度を計算する:

tan (\frac{1}{2})

= tan (\frac{1}{2})

グラフ

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