integral from 0 to 1 of usqrt(1+u^2)

Lösung

\int_{0}^{1} u 1 + u^{2} d u

\frac{2 2 - 1}{3}

Dezimale

0.60947 \dots

Schritte zur Lösung

\int_{0}^{1} u 1 + u^{2} d u

Wende U-Substitution an

= \int_{1}^{2} v^{2} d v

Wende die Potenzregel an

= [\frac{v ^{3}}{3}]_{1}^{2}

Berechne die Grenzen:

\frac{2 2}{3} - \frac{1}{3}

= \frac{2 2}{3} - \frac{1}{3}

Vereinfache

= \frac{2 2 - 1}{3}

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