integral from-1 to 0 of sin(x)

Lösung

\int_{- 1}^{0} sin (x) d x

- 1 + cos (1)

Dezimale

- 0.45969 \dots

Schritte zur Lösung

\int_{- 1}^{0} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- 1}^{0}

Berechne die Grenzen:

- 1 + cos (1)

= - 1 + cos (1)

\int_{1}^{2} e^{x} - x d x

\int_{0}^{10} x e^{- 2 x} d x

\int_{0}^{2} \frac{x}{x - 2} d x

\int_{1}^{e^{3}} \frac{4 ln ( x )}{x} d x

\int_{- 1}^{3} 3 x^{2} + 8 x d x