integral from a to b of sqrt(1+(()/1)^2)

Lösung

\int_{a}^{b} 1 + (\frac{d y}{1})^{2} d x

b d y^{2} + 1 - a d y^{2} + 1

Schritte zur Lösung

\int_{a}^{b} 1 + (\frac{d y}{1})^{2} d x

Integral einer Konstanten :

\int a d x = a x

= (\frac{d y}{1})^{2} + 1 x_{a}^{b}

Vereinfache

= [x d y^{2} + 1]_{a}^{b}

Berechne die Grenzen:

b d y^{2} + 1 - a d y^{2} + 1

= b d y^{2} + 1 - a d y^{2} + 1

\int_{3}^{4} (2 x + 2) d x

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