integral from 0 to 1 of x^3-3x^2+2

Lösung

\int_{0}^{1} x^{3} - 3 x^{2} + 2 d x

\frac{5}{4}

Dezimale

1.25

Schritte zur Lösung

\int_{0}^{1} x^{3} - 3 x^{2} + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x - \int_{0}^{1} 3 x^{2} d x + \int_{0}^{1} 2 d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 3 x^{2} d x = 1

\int_{0}^{1} 2 d x = 2

= \frac{1}{4} - 1 + 2

Vereinfache

\frac{1}{4} - 1 + 2 : \frac{5}{4}

= \frac{5}{4}

\int_{0}^{\infty} e^{- y} (2 y^{3} - \frac{2 y ^{3}}{3}) d y

\int_{1}^{9} \frac{11}{x} d x

\int_{0}^{1} x \cdot \frac{3}{2} (1 - x^{2}) d x

\int_{0}^{4} (3 3 x + x) d x

\int_{- x}^{x} e^{- x^{2}} d x