integral from 0 to x of (3+sin(t))

Lösung

\int_{0}^{x} (3 + sin (t)) d t

3 x - cos (x) + 1

Schritte zur Lösung

\int_{0}^{x} 3 + sin (t) d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} 3 d t + \int_{0}^{x} sin (t) d t

\int_{0}^{x} 3 d t = 3 x

\int_{0}^{x} sin (t) d t = - cos (x) + 1

= 3 x - cos (x) + 1

\int_{0}^{3} \frac{1}{96} y^{3} e^{- \frac{y}{2}} d y

\int_{0}^{0.9} \frac{cos ( x ) - 1}{x} d x

\int_{0}^{1} \frac{1}{( x + y + 1 ) ^{2}} d x

\int_{0}^{4} x - \frac{x ^{2}}{8} d x

\int_{0}^{1} (x^{4} - x) d x