integral from 4 to 1 of 1

Lösung

\int_{4}^{1} 1

- 3

Schritte zur Lösung

\int_{4}^{1} 1 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{4} 1 d x

Integral einer Konstanten :

\int a d x = a x

= - [1 \cdot x]_{1}^{4}

Vereinfache

= - [x]_{1}^{4}

Berechne die Grenzen:

3

= - 3

\int_{- 2}^{0} - sin (\frac{nπ x}{2}) d x

\int_{4}^{3} 1

\int_{4}^{8} \frac{x ^{2} - 16}{x} d x

\int_{0}^{4} π x d x

\int_{5 x}^{x^{4}} e^{- t^{2}} d t