integral from 1 to 2 of 1/(4x^2)

Lösung

\int_{1}^{2} \frac{1}{4 x ^{2}} d x

\frac{1}{8}

Dezimale

0.125

Schritte zur Lösung

\int_{1}^{2} \frac{1}{4 x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{1}^{2} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= \frac{1}{4} [- \frac{1}{x}]_{1}^{2}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{4} \cdot \frac{1}{2}

Vereinfache

= \frac{1}{8}

\int_{3}^{4} \frac{6}{3 x - 8} d x

\int_{0}^{3} (1) d x

\int_{3}^{4} 4 d x

\int_{3}^{5} e^{- x^{2}} x d x

\int_{0}^{1} (ln (1 + x)) d x