integral from 0 to 4 of (x+1)^3

Lösung

\int_{0}^{4} (x + 1)^{3} d x

156

Schritte zur Lösung

\int_{0}^{4} (x + 1)^{3} d x

Wende U-Substitution an

= \int_{1}^{5} u^{3} d u

Wende die Potenzregel an

= [\frac{u ^{4}}{4}]_{1}^{5}

Berechne die Grenzen:

156

= 156

\int_{- 2}^{3} (5 + x - 6 x^{2}) d x

\int_{\frac{π}{4}}^{\frac{π}{2}} sin^{5} (x) d x

\int_{0}^{t} \frac{1}{x} d x

\int_{- 1}^{1} (1 - 4 x)^{2} d x

\int_{0}^{2} 6 e^{- x^{2}} d x