derivative f(x)=3x^2+2ax+b

Lösung

ableitung von

f (x) = 3 x^{2} + 2 a x + b

6 x + 2 a

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + 2 a x + b)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 a x) + \frac{d b}{d x}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 a x) = 2 a

\frac{d b}{d x} = 0

= 6 x + 2 a + 0

Vereinfache

= 6 x + 2 a

y^{^{''}} - 2 y^{^{'}} + 5 y = 5 x + 3

x \to 3 lim (\frac{3 - x}{∣ x - 3 ∣})

\int (8 x + 1 - 9 e^{x}) d x

in v erse l a pl a ce \frac{e ^{- s}}{s ^{2} + 3 s + 2}

\int \frac{e ^{- x}}{( 9 e ^{- 2 x} + 1 ) ^{\frac{3}{2}}} d x